Por CAIQUE DIONISIO DOS SANTOS em 12/05/2017 17:16:01
A+B+C+D+E/5=90
E=130 PG
A+B+C+D/5=90
K=A,B,C,D
K+130/5=90
K=90.5-130
K=450-130
K=320/4=80
ALTERNATIVA C)80
E=130 PG
A+B+C+D/5=90
K=A,B,C,D
K+130/5=90
K=90.5-130
K=450-130
K=320/4=80
ALTERNATIVA C)80